【FUT】8个python实用脚本

无名

1.解决 linux 下 unzip 乱码的问题。import osimport sysimport zipfileimport argparse?s = '\x1b[%d;%dm%s\x1b[0m' ?def unzip(path):? file = zipfile.ZipFile(path,"r") if args.secret: file.setpassword(args.secret)? for name in file.namelist(): try: utf8name=name.decode('gbk') pathname = os.path.dirname(utf8name) except: utf8name=name pathname = os.path.dirname(utf8name)? #print s % (1, 92, ' >> extracting:'), utf8name #pathname = os.path.dirname(utf8name) if not os.path.exists(pathname) and pathname != "": os.makedirs(pathname) data = file.read(name) if not os.path.exists(utf8name): try: fo = open(utf8name, "w") fo.write(data) fo.close except: pass file.close()?def main(argv): ###################################################### # for argparse p = argparse.ArgumentParser(description='解决unzip乱码') p.add_argument('xxx', type=str, nargs='*', \ help='命令对象.') p.add_argument('-s', '--secret', action='store', \ default=None, help='密码') global args args = p.parse_args(argv[1:]) xxx = args.xxx? for path in xxx: if path.endswith('.zip'): if os.path.exists(path): print s % (1, 97, ' ++ unzip:'), path unzip(path) else: print s % (1, 91, ' !! file doesn\'t exist.'), path else: print s % (1, 91, ' !! file isn\'t a zip file.'), path?if __name__ == '__main__': argv = sys.argv main(argv)